Chemistry - Redox Reactions Question with Solution | TestHub

Write $\mathrm{N}{\mathrm{O}}_2\mathrm{Cl}{\mathrm{O}}_4$ as $\mathrm{N}{\mathrm{O}}_2^{+}$ $\mathrm{Cl}{\mathrm{O}}_4^{-}$ (nitryl perchlorate). In $\mathrm{N}{\mathrm{O}}_2^{+}$: N + 2(-2) = +1, so N is +5. In $\mathrm{Cl}{\mathrm{O}}_4^{-}$: Cl + 4(-2) = -1, so Cl is +7. Hence nitrogen is +5 and chlorine is +7.