Chemistry - Redox Reactions Question with Solution | TestHub

Solution:

Moles of KMnO₄ = $0.1M\times 0.100L=0.01mol$.

From the balanced equation, 2 moles of KMnO₄ react with 5 moles of H₂O₂.

Moles of H₂O₂ = $\frac{5}{2}\times 0.01mol=0.025mol$.

Molarity of H₂O₂ = $\frac{0.025mol}{0.280L}=0.08928M$.

Volume strength of H₂O₂ = $11.35\times Molarity=11.2\times 0.08928=1.0V$