Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsDetermination of Oxidation StateEasy2 minQB

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The compound of Xe and F is found to have 53.5% Xe. What is oxidation number of Xe in this compound? (Xe = 131)

Answer:

Solution:

For XeFₙ: 131/131 + 19n = 0.535 ⇒ 131 + 19n ≈ 245 ⇒ n = 6, so the compound is XeF₆. With F = -1, Xe = +6. Hence (d).

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Determination of Oxidation State

⏱ 2mℹ️ Source: QB

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