Chemistry - Redox Reactions Question with Solution | TestHub
Match each solution in Column I with the solution(s) in Column II needed for complete reaction.
Column I | Column II |
|---|---|
A) 200 ml of 0.15 M - solution | P) 50 ml of 0.6 M - solution |
B) 100 ml of 0.3 M - solution | Q) 120 ml of 0.1 M - solution in the presence of |
C) 30 ml of 1.0 M - solution | R) 30 ml of 0.2 M - solution in the presence of |
D) 100 ml of 0.2 M - solution | S) 150 ml of 0.4 M - solution |
Options:
Answer:
Solution:
Column II equivalents: P = 0.03 mol = 0.03 eq; Q = 0.012 mol 5 = 0.06 eq; R = 0.006 mol 5 = 0.03 eq; S = 0.06 mol = 0.06 eq. (A) 0.03 mol : as acid 0.06 eq (S); as reductant 2 per mole = 0.06 eq (Q). (B) 0.03 mol : as acid 0.03 eq (P); as reductant 0.06 eq (Q). (C) 0.03 mol : neutralization 0.03 eq (P); oxidation of to is 1 per = 0.03 eq (R). (D) 0.02 mol : complete neutralization needs 0.06 eq (S).
