Number of gram equivalent of H 2 SO 4 present in 200 ml of 10 M H 2 SO 4 solution.

Question

Number of gram equivalent of H 2 ​ SO 4 ​ present in 200 ml of 10 M ​ H 2 ​ SO 4 ​ solution.

TestHub · Accepted Answer

Number of gram equivalents of H₂SO₄ present in 200 ml of $\frac{M}{10}$ H₂SO₄ solution.

Molarity (M) = $\frac{N u mb ero f m o l eso f so l u t e}{V o l u m eo f so l u t i o nin l i t ers}$

Normality (N) = $\frac{N u mb ero f g r am e q u i v a l e n t so f so l u t e}{V o l u m eo f so l u t i o nin l i t ers}$

For H₂SO₄, Normality = Molarity $\times$ basicity

Basicity of H₂SO₄ = 2 (since it has 2 replaceable H⁺ ions)

Given: Molarity = $\frac{1}{10}$ M = 0.1 M

Volume = 200 ml = 0.2 L

Normality = 0.1 M $\times$ 2 = 0.2 N

Number of gram equivalents = Normality $\times$ Volume (in liters)

Number of gram equivalents = 0.2 N $\times$ 0.2 L = 0.04

Therefore, the number of gram equivalents of H₂SO₄ present in 200 ml of $\frac{M}{10}$ H₂SO₄ solution is 0.04.

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