In the reaction: P 4 + 3NaOH + 3 H 2 O → P H 3 + 3Na H 2 P O 2 , the equivalent weight of P H 3 is

In forming P H 3 , P goes 0 → -3, gaining 3 e − per P atom. n = 3 per mole of P H 3 , so Eq wt = M/3. Hence (b).

Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsEquivalent Weight and n-factorHard2 minQB

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In the reaction: $P_{4}$ + 3NaOH + $3 H_{2} O$ $\to$ $P H_{3}$ + $3Na H_{2} P O_{2}$ , the equivalent weight of $P H_{3}$ is

Answer:

Solution:

In forming $P H_{3}$ , P goes 0 $\to$ -3, gaining 3 $e^{-}$ per P atom. $n$ = 3 per mole of $P H_{3}$ , so Eq wt = M/3. Hence (b).

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Equivalent Weight and n-factor

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