The iodide content of a solution was determined by titration with cerium (IV) sulphate in the presence of HCl , in which I − is converted to ICl . A 100 ml sample of the solution required 25 ml of 0.0

Question

The iodide content of a solution was determined by titration with cerium (IV) sulphate in the presence of HCl , in which I − is converted to ICl . A 100 ml sample of the solution required 25 ml of 0.04 N C e 4 + solution. What is the iodide concentration in the original solution in g/L?

TestHub · Accepted Answer

I − → ICl is a 2-electron change; equivalent mass = 127/2 = 63.5. meq C e 4 + = 25 x 0.04 = 1 meq = meq I − in 100 ml. Mass = 63.5 mg in 100 ml = 0.635 g/L, option (c).

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