What is the value of n ? | TestHub

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What is the value of $n$ ?

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Answer:

C

Solution:

X goes from +n to +5 (in $X O_{3}^{-}$ ), losing (5 - $n$ ) $e^{-}$ ; $Mn O_{4}^{-}$ $\to$ $M n^{2 +}$ gains 5 $e^{-}$ in acid. Equivalents: $3.0 \times 1 0^{- 3} (5$ - $n$ ) = $1.2 \times 1 0^{- 3}$ × 5, so 5 - $n$ = 2 and $n$ = 3, matching (c).

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Titration

⏱ 2mℹ️ Source: QB

Chemistry - Redox Reactions Question with Solution | TestHub

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