Chemistry - Redox Reactions Question with Solution | TestHub

Number of mtextlli equivalents of$\text{M}\text{n}{\text{O}}_4^{-}=0.02\times 3\times 250=15$

Number of mtextlli equivalents of${\text{l}}_2=0.1\times 1\times 250=25$

Thus, here$\text{M}\text{n}{\text{O}}_4^{-}$is limtextting reagent.

$\therefore$Number of mtextlli equivalents of${\text{l}}_2$formed = Number of mtextlli equivalent of$\text{M}\text{n}{\text{O}}_4^{-}=15$

Or number of equivalent of${\text{l}}_2$formed$=\frac{15}{1000}=0.015$

$\therefore$Number of moles of${\text{l}}_2$formed$=\frac{0.015}{2}$

$=0.0075$