Chemistry - Redox Reactions Question with Solution | TestHub
ChemistryRedox ReactionsEquivalent Weight and n-factorMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
For the reaction: MnBr₂ + PbO₂ + HNO₃ HMnO₄ + Pb(BrO₃)₂ + Pb(NO₃)₂ + H₂O (Atomic masses: Mn = 55, Br = 80, Pb = 208)
The equivalent weight of PbO₂ is
Options:
Answer:
A
Solution:
Pb in PbO₂ is +4 and ends as Pb²⁺ in Pb(BrO₃)₂ and Pb(NO₃)₂, gaining 2 e⁻, so n-factor = 2. M(PbO₂) = 208 + 32 = 240. E = 240/2 = 120, matching (a).
Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Equivalent Weight and n-factor
⏱ 2mℹ️ Source: QB
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