In the balanced reaction a BrO 3 − + b Br − + c H + → d Br 2 + e H 2 O the value of ( d c ) will be:

Br ( + 5 ) in BrO 3 − gains 5 e − ; Br − loses 1 e − , so 1 : 5. BrO 3 − + 5 Br − + 6 H + → 3 Br 2 + 3 H 2 O . c = 6 , d = 3 , so c / d = 2 . Answer: (A).

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Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsBalancing of Redox ReactionsEasy2 minQB

ChemistryEasysingle choice

In the balanced reaction

$a BrO_{3}^{-} + b Br^{-} + c H^{+} \to d Br_{2} + e H_{2} O$

the value of $(\frac{c}{d})$ will be:

Options:

Answer:

Solution:

$Br (+ 5)$ in $BrO_{3}^{-}$ gains 5 $e^{-}$ ; $Br^{-}$ loses 1 $e^{-}$ , so 1 : 5.

$BrO_{3}^{-} + 5 Br^{-} + 6 H^{+} \to 3 Br_{2} + 3 H_{2} O$ .

$c = 6$ , $d = 3$ , so $c / d = 2$ .

Answer: (A).

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Balancing of Redox Reactions

⏱ 2mℹ️ Source: QB

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