Chemistry - Redox Reactions Question with Solution | TestHub
ChemistryRedox ReactionsTitrationHard2 minQB
ChemistryHardsingle choice
Passage / Comprehension
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What is the percentage of in the sample?
Options:
Answer:
B
Solution:
Against oxalate has n-factor 5, so molarity = 0.25/5 = 0.05 M; moles = 30.0 × 0.05 = 1.5 mmol. From the 4 : 1 stoichiometry, = 4 × 1.5 = 6 mmol, so = 2 mmol. Mass = 2 × 229 mg = 0.458 g. Percentage = 0.458/0.687 × 100 = 66.67%, matching (b).
Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Titration
⏱ 2mℹ️ Source: QB
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