Chemistry - Redox Reactions Question with Solution | TestHub

${\mathrm{H}}_2{\mathrm{O}}_2$ $\to$ ${\mathrm{O}}_2$ + $2{\mathrm{H}}^{+}$ + $2{\mathrm{e}}^{-}$: it loses 2 ${\mathrm{e}}^{-}$ per mole (O -1 $\to$ 0). $\mathrm{KMn}{\mathrm{O}}_4$ accepts 5 ${\mathrm{e}}^{-}$ per mole in acid. Moles of $\mathrm{KMn}{\mathrm{O}}_4$ = 2/5. Hence (a).