Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsEquivalent Weight and n-factorMedium2 minQB

ChemistryMediumsingle choice

Passage / Comprehension

$Eq u i v a l e n tw e i g h t = \frac{\frac{M o l ec u l a r w e i g h t}{A t o mi c w e i g h t}}{n - f a c t or}$

The n-factor is very important in both redox and non-redox reactions. With the help of the n-factor, we can predict the molar ratio of the reactant species taking part in reactions. In general, the n-factor of an acid/base is the number of moles of H⁺/OH⁻ furnished per mole of acid/base. The n-factor of a reactant is the number of moles of electrons lost or gained per mole of reactant.

For the reaction:

$H_{3} P O_{2} + N a O H ⟶ N a H_{2} P O_{2} + H_{2} O$

What is the equivalent weight of H₃PO₂? (mol. wt. is $M$ )

Options:

Answer:

Solution:

$H_{3} PO_{2} + NaOH ⟶ NaH_{2} PO_{2} + H_{2} O$

n.f $= 1$

eq. $wt = M$

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Equivalent Weight and n-factor

⏱ 2mℹ️ Source: QB

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