In the reaction: Pb + Pb O 2 + H 2 S O 4 → PbS O 4 + H 2 O , the equivalent weight of Pb is

Metallic lead is oxidized: Pb(0) → Pb(+2) in PbS O 4 , losing 2 e − per atom. n = 2, Eq wt = M/2. Hence (d).

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ChemistryRedox ReactionsEquivalent Weight and n-factorMedium2 minQB

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In the reaction: Pb + $Pb O_{2}$ + $H_{2} S O_{4}$ $\to$ $PbS O_{4}$ + $H_{2} O$ , the equivalent weight of Pb is

Answer:

Solution:

Metallic lead is oxidized: Pb(0) $\to$ Pb(+2) in $PbS O_{4}$ , losing 2 $e^{-}$ per atom. $n$ = 2, Eq wt = M/2. Hence (d).

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Equivalent Weight and n-factor

⏱ 2mℹ️ Source: QB

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