Consider the following reaction : CrO 5 + H 2 SO 4 → Cr 2 ( SO 4 ) 3 + H 2 O + O 2 One mole of CrO 5 will librate how many moles of O 2

2 CrO 5 + 3 H 2 SO 4 → Cr 2 ( SO 4 ) 3 + 3 H 2 O + 2 7 O 2 One mole of CrO 5 will produce 7/4 moles of O 2

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Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsBalancing of Redox ReactionsMedium2 minQB

ChemistryMediumsingle choice

Passage / Comprehension

In a balance redox reaction, net gain of electron(s) is equal to net loss of electrons(s). n_factor is a reaction specific parameter and for inter molecular redox reaction n_factor of oxidising or reducing agent is the no. of moles of electron gained / loss by one mole of compound, respectively.

Consider the following reaction : $CrO_{5} + H_{2} SO_{4} \to Cr_{2} (SO_{4})_{3} + H_{2} O + O_{2}$

One mole of $CrO_{5}$ will librate how many moles of $O_{2}$

Options:

Answer:

Solution:

$2 CrO_{5} + 3 H_{2} SO_{4} \to Cr_{2} (SO_{4})_{3} + 3 H_{2} O + \frac{7}{2} O_{2}$

One mole of $CrO_{5}$ will produce $7/4$ moles of $O_{2}$

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Balancing of Redox Reactions

⏱ 2mℹ️ Source: QB

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