1 mole of H 3 AsO 4 reacts with 1 mole of Ca ( OH ) 2 as H 3 AsO 4 + Ca ( OH ) 2 → CaHAsO 4 + 2 H 2 O (atomic weights: As = 75, Ca = 40, O = 16, H = 1). Select the correct statement(s):

Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsEquivalent Weight and n-factorMedium2 minQB

ChemistryMediummultiple choice

1 mole of $H_{3} AsO_{4}$ reacts with 1 mole of $Ca (OH)_{2}$ as

$H_{3} AsO_{4} + Ca (OH)_{2} \to CaHAsO_{4} + 2 H_{2} O$

(atomic weights: As = 75, Ca = 40, O = 16, H = 1). Select the correct statement(s):

Answer:

A, B, D

Solution:

Two $H^{+}$ of the acid are replaced, and the base supplies two $OH^{-}$ : n-factor $= 2$ for both.

$Ca (OH)_{2} = 74$ , so equivalent weight $= 74/2 = 37$ : (A) true.

$H_{3} AsO_{4} = 3 + 75 + 64 = 142$ , so equivalent weight $= 142/2 = 71$ : (B) true, (C) false (47.33 would need $n = 3$ ).

As is in +5 and can be reduced to +3, so the acid can act as an oxidising agent: (D) true.

Answer: A, B, D.

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Equivalent Weight and n-factor

⏱ 2mℹ️ Source: QB

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