Home
PYQ PracticeFree
JEE Rank Predictor
Answer Key

Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsDetermination of Oxidation StateMedium2 minQB

ChemistryMediuminteger

Passage / Comprehension

NaClO₃ on reaction with SO₂ gas in the presence of H₂SO₄ and traces of NaCl forms a yellow gas (A) as one of the products. Ozonolysis of 'A' produces 'X' along with the liberation of oxygen gas.

1 mole of ' X ' on reaction with excess of NaOH gives ' B ', ' Q ' and $H_{2} O$ . Oxidation states of central atoms in the anions of ' $B$ ' and ' $Q$ ' are ' $+ p$ ' and ' $+ q$ ' respectively. Value of $∣ q - p ∣$ is:

Answer:

Solution:

$4 ClO_{2} + 2 O_{3} \to 2 Cl_{2} O_{6} + O_{2}$

$Cl_{2} O_{6} + 2 NaOH \to NaClO_{3} + NaClO_{4} + H_{2} O$

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Determination of Oxidation State

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...