Match the reactions in Column I with the type(s) of reaction in Column II on the basis of oxidation/reduction. Column I Column II A) 2 H 2 O 2 → 2 H 2 O + O 2 P) Disproportionation B) N H 4

Question

Match the reactions in Column I with the type(s) of reaction in Column II on the basis of oxidation/reduction.

Column I	Column II
A) $2 H_{2} O_{2}$ $\to$ $2 H_{2} O$ + $O_{2}$	P) Disproportionation
B) $N H_{4} N O_{3}$ $\to$ $N_{2} O$ + $2 H_{2} O$	Q) Comproportionation
C) $CaC O_{3}$ $\to$ $CaO$ + $C O_{2}$	R) Non-redox
D) $C_{2} H_{6}$ + $7/2 O_{2}$ $\to$ $2C O_{2}$ + $3 H_{2} O$	S) Combustion
	T) Redox

TestHub · Accepted Answer

(A) O goes from -1 in H 2 ​ O 2 ​ to -2 ( H 2 ​ O ) and 0 ( O 2 ​ ); same element both oxidized and reduced: disproportionation (P), hence redox (T). (B) N at -3 ( N H 4 + ​ ) and +5 ( N O 3 − ​ ) both end near +1 in N 2 ​ O : comproportionation (Q), hence redox (T). (C) Ca +2, C +4, O -2 on both sides: non-redox (R). (D) Burning of ethane in O 2 ​ : combustion (S); C is oxidized and O 2 ​ reduced, so redox (T).

Chemistry - Redox Reactions Question with Solution | TestHub

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