Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsDetermination of Oxidation StateMedium2 minQB

ChemistryMediumsingle choice

The composition of a sample of wustite is $Fe_{0.93} O_{1.00}$ . What percentage of iron is present in the form of Fe (III) :-

Answer:

Solution:

O.N. of Fe in wustite is $= \frac{200}{93} = 2.15$

It is an intermediate value in between Fe (II) and Fe (III)

Let % of Fe (III) be a, then $2 \times (100 - a) + 3 \times a = 2.15 \times 100$

$a = 15.05$

∴ % of Fe(III) $= 15.05%$

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Determination of Oxidation State

⏱ 2mℹ️ Source: QB

Loading discussions...