If 91 g V₂O₅ is dissolved in acid and reduced to V²⁺ by treatment with zinc metal, how many grams of I₂ could be reduced by the resulting V²⁺ solution, as it is oxidized to V⁴⁺? (V = 51, I = 127) V₂O₅

Question

If 91 g V₂O₅ is dissolved in acid and reduced to V²⁺ by treatment with zinc metal, how many grams of I₂ could be reduced by the resulting V²⁺ solution, as it is oxidized to V⁴⁺? (V = 51, I = 127) V₂O₅ + 10H⁺ + 6e⁻ → 2V²⁺ + 5H₂O; V²⁺ + I₂ + H₂O → 2I⁻ + VO²⁺ + 2H⁺

TestHub · Accepted Answer

Moles V₂O₅ = 91/182 = 0.5 mol, giving 1.0 mol V²⁺. Oxidation V²⁺ → V⁴⁺ releases 2e⁻ per V, so 1.0 mol V²⁺ supplies 2.0 mol e⁻, which reduces 1.0 mol I₂ (I₂ + 2e⁻ → 2I⁻). Mass I₂ = 254 g. Ans 0254.

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