One mole of N 2 H 4 looses ten moles of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y? (there is no chang

Question

One mole of N 2 H 4 looses ten moles of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y? (there is no change in the oxidation state of hydrogen)

TestHub · Accepted Answer

N 2 H 4 → Y + 10 e - Oxidation state of N in N 2 H 4 : 2 X + 4 = 0 X = - 2 The two, nitrogen atoms will balance the charge of 10 e - 1 . So, oxidation state of N will increase by +5, that is., from -2 to +3.

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