Chemistry - Redox Reactions Question with Solution | TestHub

The balance ionic equation for the reaction is ${\mathrm{MnO}}_4^{-}+5{\mathrm{Fe}}^{2+}+8{\mathrm{H}}^{+}⟶{\mathrm{Mn}}^{2+}+5{\mathrm{Fe}}^{3+}+4{\mathrm{H}}_2\mathrm{O}$ From the above equation it is clear that 1 mole of ${\mathrm{KMnO}}_4=5$ moles of ${\mathrm{FeSO}}_4$. Apply molarity equation to balance the redox reaction $\begin{array}{rl}\frac{M_1{V}_1}{n_1}\left({\mathrm{KMnO}}_4\right)& =\frac{M_2{V}_2}{n_2}\left({\mathrm{FeSO}}_4\right)\\ \frac{1\times V_1}{8\times 1}& =\frac{1}{4}\times \frac{25}{5}\\ V_1& =\frac{1\times 25\times 8}{4\times 5}\\ V_1& =10{\mathrm{cm}}^3\text{ or }{V}_1=10.0\mathrm{mL}\end{array}$