Chemistry - Redox Reactions Question with Solution | TestHub

The half reaction are (i) ${\mathrm{MnO}}_4^{-}+8{\mathrm{H}}^{+}+5{\mathrm{e}}^{-}⟶{\mathrm{Mn}}^{2+}+4{\mathrm{H}}_2\mathrm{O}$ (Reduction) (ii) ${\mathrm{H}}_2{\mathrm{C}}_2{\mathrm{O}}_4⟶2{\mathrm{CO}}_2+2{\mathrm{H}}^{+}+2{\mathrm{e}}^{-}$(Oxidation) To get balance net reaction, multiply equation (i) by 2 and equation (ii) by 5, then on adding, we get $2{\mathrm{MnO}}_4^{-}+5{\mathrm{H}}_2{\mathrm{C}}_2{\mathrm{O}}_4+6{\mathrm{H}}^{+}\underset{2{\mathrm{Mn}}^{2+}}{\to }+10{\mathrm{CO}}_2+8{\mathrm{H}}_2\mathrm{O}$ Thus, $x=2,y=5,m=2,n=10$ $x+y+m+n=2+5+2+10$ $\therefore$ Sum of $x,y,m$ and $n$ is 19.