Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

The combustion of sodium in excess air yields a higher oxide. What is the oxidation state of the oxygen in the product? Neglect the negative sign.

Answer:

1.00

Solution:

$Na + O_{2} \to {Na}_{2} O, {Na}_{2} O + \frac{1}{2} O_{2} \to {Na}_{2} O_{2}$

It exists as $2 {Na}^{+}$ and $O_{2}^{2 -}$

So oxidation state of O is $- 1$

Stream:NTA_ABHYASSubject:ChemistryTopic:Redox ReactionsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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