Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsTitrationHard2 minQB
ChemistryHardnumerical

A 10 g mixture of and was treated with 300 ml of 0.5 M - in acid solution producing , and . The was boiled off and the excess of was titrated with 175 ml of 1 M - solution. The percentage of in original mixture is (Cu = 64)

Answer:
60.00
Solution:

taken = = 150 mmol. Excess = 175/5 = 35 mmol; consumed = 115 mmol = 575 meq. Let a, b = mol (M = 160) and (M = 96): 160a+96b = 10; 8a+6b = 0.575. Solving, a = 0.025, b = 1/16 mol; mass = 96/16 = 6 g 60%. Ans 0060.

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Titration
⏱ 2mℹ️ Source: QB

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