What is the atomic mass of X, if the mass of 1 g-equivalent of XC l n in this | TestHub

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What is the atomic mass of X, if the mass of 1 g-equivalent of $XC l_{n}$ in this reaction is 79.25? $XC l_{n}$ is the molecular form of $x^{+ n}$ .

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Answer:

A

Solution:

n-factor of $XC l_{3}$ in this oxidation = 2, so $M (XC l_{3})$ = 2 × 79.25 = 158.5. Atomic mass of X = 158.5 - 3 × 35.5 = 158.5 - 106.5 = 52, matching (a).

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Equivalent Weight and n-factor

⏱ 2mℹ️ Source: QB

Chemistry - Redox Reactions Question with Solution | TestHub

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