Consider the following reaction : x MnO 4 - + y C 2 O 4 2 - + z H + ⟶ x Mn 2 + + 2 y CO 2 + z 2 H 2 O The values of x, y and z in the reaction are, respectively :

C 2 O 4 2 - ⟶ 2 CO 2 + 2 e - ] × 5 MnO 4 - + 8 H + + 5 e - ⟶ Mn 2 + + 4 H 2 O ] × 2 ----------------------------------------------------------------------------------- 2 MnO 4 - + 1 6 H + + 5 C 2 O 4 2 - ⟶ 1 0 CO 2 + 2 Mn 2 + + 8 H 2 O MnO 4 - ⇒ x = 2 C 2 O 4 2 - ⇒ y = 5 H + ⇒ z = 1 6

Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsBalancing of Redox ReactionsEasy2 minPYQ_2020

ChemistryEasysingle choice

Consider the following reaction :

$x {MnO}_{4}^{-} + y C_{2} O_{4}^{2 -} + z H^{+} ⟶ x {Mn}^{2 +} + 2 y {CO}_{2} + \frac{z}{2} H_{2} O$

The values of x, y and z in the reaction are, respectively :

Options:

Answer:

Solution:

$\begin{matrix} C_{2} O_{4}^{2 -} & ⟶ & 2 {CO}_{2} + 2 e^{-}] \times 5 \\ {MnO}_{4}^{-} + 8 H^{+} + 5 e^{-} & ⟶ & {Mn}^{2 +} + 4 H_{2} O] \times 2 \end{matrix}$
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$\begin{matrix} 2 {MnO}_{4}^{-} + 16 H^{+} + 5 C_{2} O_{4}^{2 -} & ⟶ \end{matrix} 10 {CO}_{2} + 2 {Mn}^{2 +} + 8 H_{2} O$

${MnO}_{4}^{-} \Rightarrow x = 2$

$C_{2} O_{4}^{2 -} \Rightarrow y = 5$

$H^{+} \Rightarrow z = 16$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Redox ReactionsSubtopic:Balancing of Redox Reactions

⏱ 2mℹ️ Source: PYQ_2020

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