The volume of 0.1 M strong dibasic acid sufficient to neutralize 1g of a base that furnishes 0.04 mole of O H - in aqueous solution is :

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For neutralisation; ⇒ n o . o f m o l e s o f H + = n o . o f m o l e s o f O H - ⇒ 2 × M a V a = 0.04 ⇒ 2 × 0.1 × V a = 0.04 ⇒ V a = 0.04 0.2 = 0.2 L = 200 mL

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