Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsProblem involving Equivalent ConceptHard2 minPYQ_2011

ChemistryHardsingle choice

$1.520 g$ of hydroxide of a metal on ignition gave $0.995 g$ of oxide. The equivalent weight of metal is:

Options:

Answer:

Solution:

Let $E$ be the equivalent weight of the metal $So, \frac{E + 17}{E + 8} = \frac{1.52}{0.995}$ [17 is equivalent weight of $OH$ and 8 is equivalent weight of oxygen] $\Rightarrow 0.995 E + 17 \times 0.995 = E \times 1.52 + 8 \times 1.52 \Rightarrow 0.525 E = 16.915 - 12.16 = 4.755 ∴ E = \frac{4.755}{0.525} = 9$

Stream:BITSATSubject:ChemistryTopic:Redox ReactionsSubtopic:Problem involving Equivalent Concept

⏱ 2mℹ️ Source: PYQ_2011

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