Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsEquivalent Weight and n-factorMedium2 minQB

ChemistryMediumsingle choice

In basic medium, $CrO_{4}^{2 -}$ oxidizes $S_{2} O_{3}^{2 -}$ to form $SO_{4}^{2 -}$ and itself changes to $Cr (OH)_{4}^{-}$ . How many ml of $0.154 M CrO_{4}^{2 -}$ are required to react with 40 ml of $0.246 M S_{2} O_{3}^{2 -}$ ?

Options:

Answer:

Solution:

$40 \times 0.246 \times 8 = V \times 0.154 \times 3$

(Meq. of $S_{2} O_{3}^{2 -} =$ Meq. of $CrO_{4}^{2 -}$ )

$∴ V = 170.4 ml$

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Equivalent Weight and n-factor

⏱ 2mℹ️ Source: QB

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