For real gas, we can write the virial equation as: P V m = RT [ 1 + V m B + V m 2 C + … ] where B and C are virial coefficients. At 300 K for 1 m o l e real gas, the value of B = 0.004 L m o

Question

For real gas, we can write the virial equation as:

$P V_{m} = RT [1 + \frac{B}{V _{m}} + \frac{C}{V _{m}^{2}} + \dots]$

where $B$ and $C$ are virial coefficients. At $300 K$ for $1 m o l e$ real gas, the value of $B = 0.004 L m o l^{- 1}$ and $C = 0.0036 L^{2} m o l^{- 2}$ . Calculate the temperature (in K) of the real gas above which it is not liquefied on applying pressure.

(Given: $R = \frac{1}{12} L a t m K^{- 1} m o l^{- 1}$ )

TestHub · Accepted Answer

B = 0.004 = b − RT a ​ ⇒ a = 1.4 ​ C = b 2 = 0.0036 ⇒ b = 0.06 ​ ​ T C ​ = 27 Rb 8 a ​ = 82.96

Chemistry - Real Gas Question with Solution | TestHub

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