At moderate pressures, the compressibility factor of a gas is given by: Z = 1 + 0.4 P − T 200 P (P in bars and T in Kelvin) The Boyle’s temperature is given by:

At Boyle's temperature, Z → 1 ⇒ 0.4 P − T 200 P = 0

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At moderate pressures, the compressibility factor of a gas is given by:

$Z = 1 + 0.4 P - \frac{200 P}{T}$ (P in bars and T in Kelvin)

The Boyle’s temperature is given by:

Answer:

Solution:

At Boyle's temperature, Z → 1

$\Rightarrow 0.4 P - \frac{200 P}{T} = 0$

Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Boyle Temperature

⏱ 2mℹ️ Source: QB

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