A van der Waals gas has a Boyle temperature of 810 K and a critical pressure of 30 atm. Its critical volume, in mL / mol , is ( R = 0.082 L atm K − 1 mol − 1 )

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T c ​ = ( 8/27 ) T B ​ = ( 8/27 ) × 810 = 240 K b = R T c ​ / ( 8 P c ​ ) = 0.082 × 240/ ( 8 × 30 ) = 0.082 L / mol . V c ​ = 3 b = 0.246 L / mol = 246 mL / mol . Answer: 246.

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