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Chemistry - Real Gas Question with Solution | TestHub

ChemistryReal GasVander Waal's Gas EquationMedium2 minQB

ChemistryMediumnumerical

For one mole of a van der Waals gas when $b = 0$ and $T = 300 K$ , the PV vs. $1/ V$ plot is shown below. The value of the van der Waals constant a $(atm$ litre $^{2} mol^{- 2})$ is :

Answer:

1.50

Solution:

For 1 mole gas with b = 0, van der Waals equation becomes:

This is of the form y = c + mx, where slope = –a and intercept = RT.

From graph: intercept ≈ 24.6 ⇒ matches .

Take two points: (2, 21.6) and (3, 20.1)

Slope =

Thus, a = 1.5 atm L² mol⁻²

Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Vander Waal's Gas Equation

⏱ 2mℹ️ Source: QB

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