2 mol of C O 2 ( a = 3.59 atm L 2 / mol 2 , b = 0.0427 L / mol ) are held in a 5.0 L vessel at 300 K. Using the van der Waals equation, the pressure of the gas in atm (up to two decimal places) is (

Question

2 mol of C O 2 ​ ( a = 3.59 atm L 2 / mol 2 , b = 0.0427 L / mol ) are held in a 5.0 L vessel at 300 K. Using the van der Waals equation, the pressure of the gas in atm (up to two decimal places) is ( R = 0.0821 L atm K − 1 mol − 1 )

TestHub · Accepted Answer

P = n RT / ( V − nb ) − a n 2 / V 2 . n RT = 2 × 0.0821 × 300 = 49.26 L atm ; V − nb = 5.0 − 0.0854 = 4.9146 L . n RT / ( V − nb ) = 10.02 atm and a n 2 / V 2 = 3.59 × 4/25 = 0.574 atm . P = 10.02 − 0.574 = 9.45 atm . Trap: using the ideal gas value gives 9.85 atm. Answer: 9.45.

Chemistry - Real Gas Question with Solution | TestHub

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