The equation of state for a van der Waal gas can be expressed as Z = 1 + B/V m + C/V m 2 + .... If the van der Waal constants a and b are 1.344 litre 2 atm/mol 2 and 0.03 litre mol -1 , respectively,

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The equation of state for a van der Waal gas can be expressed as Z = 1 + B/V m + C/V m 2 + .... If the van der Waal constants a and b are 1.344 litre 2 atm/mol 2 and 0.03 litre mol -1 , respectively, then the value of second virial coefficient (in litre/mol) for oxygen gas at 0°C is

TestHub · Accepted Answer

For a van der Waals gas, B = b - a/(RT). At 273 K: a/(RT) = 1.344/(0.0821 × 273) = 1.344/22.41 = 0.06 l mol -1 . So B = 0.03 - 0.06 = -0.03 l/mol. Ans: (a)

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