Chemistry - Real Gas Question with Solution | TestHub

ChemistryReal GasLiquification & Critical Constants of GasesMedium2 minQB
ChemistryMediumsingle choice

Consider the following statements:

1. Molecules of different ideal gases have the same translational kinetic energy at a given temperature.

2. The total translational kinetic energy for two moles of an ideal gas is equal to 3RT.

3. At critical temperature, the intermolecular forces between gas molecules vanishes.

4. The gas with a larger value of the ratio of critical temperature to critical pressure will have larger value of excluded volume.

Options:

Answer:
D
Solution:

Statement 1 is correct: average translational KE = 3/2kT per molecule, same for all gases at the same T. Statement 2 is correct: for 2 moles, total translational KE = 2 × 3/2RT = 3RT. Statement 3 is wrong: at TC the intermolecular forces do not vanish; the liquid and gas phases merely become indistinguishable. Statement 4 is correct: b = (RTC)/(8PC), so a larger TC/PC ratio means a larger b, i.e. larger excluded volume. Hence 1, 2 and 4 are correct. Ans: (d)

Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Liquification & Critical Constants of Gases
⏱ 2mℹ️ Source: QB

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