Chemistry - Real Gas Question with Solution | TestHub

Here the given equation is$\mathrm{P}(\mathrm{V}-\mathrm{b})=\mathrm{RT}$.
On comparing with van der Waals' equation
$\left[\mathrm{P}+\frac{\mathrm{a}}{{\mathrm{V}}^2}\right][\mathrm{V}-\mathrm{b}]=\mathrm{R}\mathrm{T}$
That is$\mathrm{a}=0$.
It means only repulsive forces are present which are contributive only at very close distance so the potential energy will increase abruptly. i.e., graph C is correct.