Chemistry - Real Gas Question with Solution | TestHub
ChemistryReal GasCompressibility FactorHard2 minQB
ChemistryHardmultiple choice
At very high pressure, the compressibility factor of 1 mole of a van der Waal's gas can be given as
Options:(select one or more)
Answer:
A, B
Solution:
At very high pressure, V approaches b and the attraction term is negligible: P(V − b) = RT. Then Z = PV/RT = V/(V − b) (a ✓), and expanding, V/(V − b) ≈ 1 + b/V ≈ 1 + bP/RT (b ✓). (c) is the low-pressure attraction-dominated form and (d) is algebraically wrong. Hence (a) and (b).
Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Compressibility Factor
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...
