If the Boyle's temperature for a Vander waal's gas (X) is 1260 K, then calculate the Vander waal's constant 'a', if 1 mole of the gas occupies 0.2 L at critical pressure and critical temperature.
[Given : R = 1/12 L⋅atm K^-1 mol^-1 ; Unit of 'a' should be atm⋅L² mol^-2 .]

Question

If the Boyle's temperature for a Vander waal's gas (X) is 1260 K, then calculate the Vander waal's constant 'a', if 1 mole of the gas occupies 0.2 L at critical pressure and critical temperature.

[Given : R = 1/12 L⋅atm K^-1 mol^-1 ; Unit of 'a' should be atm⋅L² mol^-2 .]

TestHub · Accepted Answer

T B ​ ∴ a ​ = R b a ​ ; V c ​ = 3 b = R T B ​ × ( 3 V C ​ ​ ) = 12 1 ​ × 1260 × 3 0.2 ​ = 7 ​

Chemistry - Real Gas Question with Solution | TestHub

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