List - I (condition of van-der-waal's gas) List - II (compressibility factor) (I) At low to moderate pressure (P) Z = 1 + RT Pb (II) At critical condition (Q) Z = 1 − V m RT a (III) For H 2

Question

List - I (condition of van-der-waal's gas)	List - II (compressibility factor)
(I) At low to moderate pressure	(P) $Z = 1 + \frac{Pb}{RT}$
(II) At critical condition	(Q) $Z = 1 - \frac{a}{V _{m} RT}$
(III) For $H_{2}$ & helium gas at room temperature	(R) Z = 3/8
(IV) At very low pressure & high temperature	(S) Z = 1
	(T) Positive derivation from ideality
	(U) Negative derivation from ideality

TestHub · Accepted Answer

Question Explanation: Match van der Waals conditions with compressibility factor Z .

Concept: van der Waals Gas Behaviour.

Solution: The van der Waals equation simplifies under different pressure and temperature conditions, resulting in distinct expressions for the compressibility factor Z .

(I) Low Pressure: $Z = 1 - \frac{a}{V _{m} RT} ($ Negative deviation $) \to Q, U$

(II) Critical Condition: $Z = 3/8 \to R$

(III) $H_{2}$ & He: $Z = 1 + \frac{Pb}{R T}$ (Positive deviation) $\to P, T$

(IV) Very Low P, High T: Z $= 1$ (Ideal behaviour) → S

Final Answer: Option (B)

Chemistry - Real Gas Question with Solution | TestHub

Options:

Doubts & Discussion