Chemistry - PRACTICAL ORGANIC CHEMISTRY Question with Solution | TestHub

Percentage of carbon $=\frac{12\times {\mathrm{m}}_2\times 100}{44\times \mathrm{m}}$ $\mathrm{m}=$ mass of organic compound $=0.3\mathrm{g}$ ${\mathrm{m}}_2=$ mass of carbon dioxilde $=0.2\mathrm{g}$ $\therefore \%C=\frac{12\times 0.2\times 100}{44\times 0.3}=18.18\%$ Percentage of hydrogen $=\frac{2\times {\mathrm{m}}_1\times 100}{18\times \mathrm{m}}$ ${\mathrm{m}}_1=$ mass of water $=0.1\mathrm{g}$ $\therefore \%\mathrm{H}=\frac{2\times 0.1\times 100}{18\times 0.3}=3.70\%$