An organic compound is subjected to chlorination to get compound A using 5 . 0 g of chlorine. When 0 . 5 g of compound A is reacted with AgNO 3 [Carius Method], the percentage of chlorine in compound

Question

An organic compound is subjected to chlorination to get compound $A$ using $5.0 g$ of chlorine. When $0.5 g$ of compound $A$ is reacted with ${AgNO}_{3}$ [Carius Method], the percentage of chlorine in compound $A$ is when it forms $0.3849 g$ of $AgCl .$ (Round off to the Nearest Integer)
(Atomic masses of $Ag$ and $Cl$ are $107.87$ and $35.5$ respectively)

TestHub · Accepted Answer

n Cl in compound = n AgCl = 0 . 3849 g ( 107 . 87 + 35 . 5 ) g / mol ⇒ mass of chlorine = n Cl × 35 . 5 = 0 . 0953 gm ⇒ % wt. of chlorine = 0 . 0953 0 . 5 × 100 = 19 . 06 %

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