Chemistry - PERIODIC TABLE Question with Solution | TestHub

Consider Electronic configuration of${\text{M}}^{\text{+}}$
${}_{\text{23}}{\text{V}}^{\text{+}}{\Rightarrow }_{\text{18}}\text{[Ar]}{\text{4s}}^{\text{1}}{\text{3d}}^{\text{3}}$
${}_{\text{24}}{\text{Cr}}^{\text{+}}{\Rightarrow }_{\text{18}}\text{[Ar]}{\text{4s}}^{\text{0}}{\text{3d}}^{\text{5}}$
${}_{\text{25}}{\text{Mn}}^{\text{+}}{\Rightarrow }_{\text{18}}\text{[Ar]}{\text{4s}}^{\text{1}}{\text{3d}}^{\text{5}}$
${}_{\text{26}}{\text{Fe}}^{\text{+}}{\Rightarrow }_{\text{18}}\text{[Ar]}{\text{3d}}^{\text{6}}{\text{4s}}^{\text{1}}$
Removal of second electron from stable configuration of${}_{\text{18}}\text{[Ar]}{\text{4s}}^{\text{0}}{\text{3d}}^{\text{5}}$will require very high energy input i.e.$\text{(Cr)}$as it will disturb the stable electronic configuration of${\text{3d}}^{\text{5}}$(half filled subshell).