Chemistry - PERIODIC TABLE Question with Solution | TestHub

${\mathrm{d}}_{\mathrm{AB}}={\gamma }_{\mathrm{A}}+{\gamma }_{\mathrm{B}}-0.09\left(\Delta {\mathrm{EN}}_{\mathrm{AB}}\right)$ where ${\gamma }_{\mathrm{A}}$ is the covalent radius of A.

Given $2.11=2.2-0.09\Delta \mathrm{EN}$, ${\gamma }_B$ is the covalent radius of B.

$\Delta \mathrm{EN}=1$ $d_{\mathrm{AB}}=BondlengthofA\&B$

The percentage ionic character (%IC) in terms of $\Delta \mathrm{EN}$ is given by:

$\%\mathrm{IC}=16|\Delta \mathrm{EN}|+3.5|\Delta \mathrm{EN}{|}^2$

Substituting $\Delta \mathrm{EN}=1$:

$\%\mathrm{IC}=16\times 1+3.5\times 1^2$

$\%\mathrm{IC}=16+3.5$

$\%\mathrm{IC}=19.5\%$

If ${\mathrm{EN}}_{\mathrm{B}}>{\mathrm{EN}}_{\mathrm{A}}$,

then the conjugate base of acid BOH (i.e., BO⁻) is more stable than the conjugate base of acid AOH (i.e., AO⁻) due to the higher electronegativity of B. Therefore, BOH is more acidic compared to AOH.

Pnictogen family refers to Group 15 elements.

B from halogen family

The molecule ${\mathrm{CB}}_3$ has a pyramidal shape.