Match List- I with List- II . List- I Electronic configuration of elements List- II Δ i H in kJ mol - 1 a 1 s 2 2 s 2 p 801 b 1 s 2 2 s 2 2 p 4 q 899 c 1 s 2 2 s 2 2 p 3 r 1314 d 1 s 2 2 s 2 2 p 1 s 1

Question

Match List- I with List- II . List- I Electronic configuration of elements List- II Δ i H in kJ mol - 1 a 1 s 2 2 s 2 p 801 b 1 s 2 2 s 2 2 p 4 q 899 c 1 s 2 2 s 2 2 p 3 r 1314 d 1 s 2 2 s 2 2 p 1 s 1402 Choose the most appropriate answer from the options given below:

TestHub · Accepted Answer

(a) 1 s 2 2 s 2 → Be (b) 1 s 2 2 s 2 2 p 4 → O (c) 1 s 2 2 s 2 2 p 3 → N (d) 1 s 2 2 s 2 2 p 1 → B The ionization enthalpy order is B < Be < O < N Be has more IE compared to B due to extra stability & N has more IE compared to oxygen due to extra stability Hence, N → 1402 kJ mol - 1 O → 1314 kJ mol - 1 B → 801 kJ mol - 1 Be → 899 kJ mol - 1

	List- $I$ Electronic configuration of elements		List- $II$ $Δ_{i} H$ in $kJ {mol}^{- 1}$
$(a)$	$1 s^{2} 2 s^{2}$	$(p)$	$801$
$(b)$	$1 s^{2} 2 s^{2} 2 p^{4}$	$(q)$	$899$
$(c)$	$1 s^{2} 2 s^{2} 2 p^{3}$	$(r)$	$1314$
$(d)$	$1 s^{2} 2 s^{2} 2 p^{1}$	$(s)$	$1402$

Chemistry - PERIODIC TABLE Question with Solution | TestHub

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