Chemistry - PERIODIC TABLE Question with Solution | TestHub

ChemistryPERIODIC TABLEMiscellaneous/MixedEasy2 minPYQ_2020
ChemistryEasysingle choice

The correct code for stability, of oxidation states for given cations is
I.Pb2+>Pb4+,Tl+<Tl3+II.Bi3+<Sb3+,Sn2+<Sn4+
III.Pb2+>Pb4+,Bi3+>Bi5+IV.Tl3+<In3+,Sn2+>Sn4+
V.Sn2+<Pb2+,Sn4+>Pb4+VI.Sn2+<Pb2+,Sn4+<Pb4+

Options:

Answer:
C
Solution:

Due to inert effect the stability of lower oxidation state gradually increases while stability of higher oxidation state gradually decreases down the group in elements of group 13th to 15th. So correct order are
III.Pb2+>Pb4+,Bi3+>Bi5+
IV.Sn2+<Pb2+,Sn4+<Pb4+

Stream:NTA_ABHYASSubject:ChemistryTopic:PERIODIC TABLESubtopic:Miscellaneous/Mixed
2mℹ️ Source: PYQ_2020

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