Chemistry - PERIODIC TABLE Question with Solution | TestHub

If we consider the opposite process
$\left(\mathrm{A}\right){\mathrm{F}}_{\left(\mathrm{g}\right)}+{\mathrm{e}}^{-}\to {\mathrm{F}}_{\left(\mathrm{g}\right)}^{-}$;$∆{\mathrm{H}}_1$
$\left(\mathrm{B}\right){\mathrm{P}}_{\left(\mathrm{g}\right)}+{\mathrm{e}}^{-}\to {\mathrm{P}}_{\left(\mathrm{g}\right)}^{-}$;$∆{\mathrm{H}}_2$
$\left(\mathrm{C}\right){\mathrm{S}}_{\left(\mathrm{g}\right)}+{\mathrm{e}}^{-}\to {\mathrm{S}}_{\left(\mathrm{g}\right)}^{-}$;$∆{\mathrm{H}}_3$
$\left(\mathrm{D}\right){\mathrm{C}\mathrm{l}}_{\left(\mathrm{g}\right)}+{\mathrm{e}}^{-}\to {\mathrm{C}\mathrm{l}}_{\left(\mathrm{g}\right)}^{-}$;$∆{\mathrm{H}}_4$
Order of energy releases is :$∆{\mathrm{H}}_4>∆{\mathrm{H}}_1>∆{\mathrm{H}}_3>∆2$
So,${\mathrm{P}}_{\left(\mathrm{g}\right)}^{-}\to {\mathrm{P}}_{\left(\mathrm{g}\right)}+{\mathrm{e}}^{-}$; Requires least energy.