Electronic configuration of four elements $A, B, C$ and D are given below :
(A) $1 s^{2} 2 s^{2} 2 p^{3}$
(B) $1 s^{2} 2 s^{2} 2 p^{4}$
(C) $1 s^{2} 2 s^{2} 2 p^{5}$
(D) $1 s^{2} 2 s^{2} 2 p^{2}$
Which of the following is the correct order of increasing electronegativity (Pauling's scale)?

Question

TestHub · Accepted Answer

N : − 1 s 2 2 s 2 2 p 3 (Electronegativity = 3 ) O : − 1 s 2 2 s 2 2 p 4 (Electronegativity = 3.5 ) F : − 1 s 2 2 s 2 2 p 5 (Electronegativity = 4 ) C : − 1 s 2 2 s 2 2 p 2 (Electronegativity = 2.55 ) Correct order = C > B > A > D

Chemistry - PERIODIC TABLE Question with Solution | TestHub

Options:

Doubts & Discussion